Cevap :
[tex]Merhaba,\\ \\ sin1=x\\ \\ sin1.( \dfrac{1}{cos0.cos1}+\dfrac{1}{cos1.cos2} +\dfrac{1}{cos2.cos3} +...+\dfrac{1}{cos44.cos45} )\\ \\ \\ =( \dfrac{sin(1-0)}{cos0.cos1}+\dfrac{sin(2-1)}{cos1.cos2} +\dfrac{sin(3-2)}{cos2.cos3} +...+\dfrac{sin(45-44)}{cos44.cos45} )\\ \\ \\ =tan1-tan0+tan2-tan1+...+tan45-tan44\\ \\ =tan45-tan1=1-tan1 \\ \\ \\ Cevap = \dfrac{1-tan1}{x} \\ \\ \\ Basarilar..[/tex]